The radius of the circular path of a charged particle in a magnetic field is given by
- A. r equals qB over mv
- B. r equals mv over qB
- C. r equals mvB over q
- D. r equals qvB
Explanation
Equating the magnetic force qvB to the required centripetal force mv squared over r and rearranging gives r equal to mv over qB. A heavier or faster particle therefore curves less, while a stronger field curves it more tightly. Because the radius depends on mass for a given charge and speed, this expression is the basis of the mass spectrometer.
Related questions
A charged particle moving parallel to a magnetic field experiences a force of
A charged particle entering a uniform magnetic field at right angles to it follows
The magnetic force on a moving charge does no work on it because the force is
In a mass spectrometer, ions of the same charge and speed but different masses are separated because