A mass of 100 kg in an elevator is descending with a = 1m/sec2. Its apparent weight will be:
Correct answer: B. 880 N
- A. 1080 N
- B. 880 N
- C. 980 N
- D. 100 N
Explanation
As the escalator is descending downwards with some acceleration, the formula to calculate the apparent weight becomes = mg-maEntering the values given in calculation , W' =(100 x 9.81)-(100 x 1)W' = 881 NHence the correct option is B.
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