A spring obeying Hook's law has an unstretched length of 50mm and a spring constant of 400 Nm -1. What is the tension in the spring when its overall length is 70mm?
Correct answer: A. 8.0N
- A. 8.0N
- B. 28N
- C. 160N
- D. 400N
Explanation
In order to find the displacement x we subtract the untstrected length from the overall length. The stretched length is equal to displacement x.70-50=20F = kxF = 20*10-3*400F = 8 N
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