A wire of length L is stretched by a length l when a force F is applied at one end. If the elastic limit is not exceeded, the amount of energy stored in the wire is
Correct answer: B. 1/2Fl
- A. Fl
- B. 1/2Fl
- C. Fl^2 /L
- D. 1/2fl^2
Explanation
The amount of energy stored in an elastic material when stretched is given by the formula 1/2 * force * extension. In this case, the force is F and the extension is l. Therefore, the energy stored in the wire is 1/2 * (F * l).
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Solids are compared through crystal structure, amorphous arrangement, elasticity, plastic deformation, stress, strain and Young’s modulus. Electrical behavior depends on available charge carriers and band structure, so conductors, insulators and semiconductors must be distinguished from mechanical properties such as strength, stiffness and brittleness.
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