Moderate

α and β-glucose differ in the orientation of -OH group around:

Correct answer: C. C1

  • A. C3
  • B. C5
  • C. C1
  • D. C2

Explanation

The correct answer is C1 because α and β-glucose differ in the orientation of the hydroxyl (-OH) group at the anomeric carbon, which is C1. In α-glucose, the -OH group on C1 is positioned on the opposite side of the ring compared to the CH2OH group, while in β-glucose, it is on the same side. The other carbon positions (C2, C3, and C5) do not affect the anomeric nature of glucose, thus these options are incorrect.

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