Find the gravitational force of attraction between two balls each weighing 10 kg, when placed at a distance of 1 meter apart.
Correct answer: A. 6.673 x 10^-9 N
- A. 6.673 x 10^-9 N
- B. 7.71 x 10^-9 N
- C. 8.91 x 10^-9 N
- D. 9.91 x 10^-9 N
- E. 10.31 x 10^-9 N
Explanation
F = (G * m1 * m2) / r2 where F is the gravitational force, G is the gravitationalconstant (approximately 6.674 × 10-11 N m2/kg2), m1 and m2 are the masses ofthe objects and r is the distance between their centers. Given that both balls weigh 10 kg and are placed 1 meter apart,we can substitute the values into the formula: F = (6.674 × 10-11 N m2/kg2 * 10 kg * 10 kg) / (1 m)2 F = (6.674 × 10-11 N m2/kg2 * 100 kg2) / 1 m2 F = 6.674 × 10-9 N Therefore, the gravitational force of attraction between thetwo balls weighing 10 kg each, when placed 1 meter apart, is approximately6.674 × 10-9 Newtons.
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Newton’s law of universal gravitation relates the force between masses to their masses and separation, while gravitational field strength explains weight and orbital motion. The topic covers satellite velocity and period, escape ideas, weightlessness in free fall, and artificial gravity, which differs from ordinary gravitational attraction.
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