How many turns of Calvin Cycle yield one molecule of glucose?

Explanation

Carbon dioxide fixation occurs during Calvin cycle. There are three stages in the process of Clavin cycle as carboxylation, reduction, and regeneration. One turn of Calvin cycle fixes one molecule of carbon dioxide. There are 6 atoms of carbon required for the synthesis of one glucose molecule. Hence, to produce one molecule of hexose sugar, six turns of Calvin cycle are required. Thus, the correct answer is option B. The other options are incorrect. Four turns of the Calvin cycle would not be enough to produce one molecule of glucose, and eight turns would be excessive. Two turns of the Calvin cycle would produce one molecule of glyceraldehyde-3-phosphate (G3P), which is a precursor to glucose.