If a plant cell with a solute potential of −0.65 kPa is placed in a solution having water potentialof −3.65 kPa, then its pressure potential will be:
Correct answer: C. −3.0 kPa
- A. 3.0 kPa
- B. 4.3 kPa
- C. −3.0 kPa
- D. −4.3 kPa
Explanation
Water potential = solute potential + pressure potential-3.65+(-0.65)= pressure potentialPressure potential = -3.0kpaSo C is correct option.
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About Plant Nutrition and Transport
Plants require macronutrients and micronutrients for growth, and mineral deficiencies produce recognizable symptoms. Transport involves water and minerals through xylem by transpiration pull, cohesion and adhesion, while phloem translocates sugars from sources to sinks. Root pressure and transpiration are distinct mechanisms.
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