In birds the male is the homogametic sex. A male bird showing the recessive trait was mated with a female showing the dominant trait of a characteristic governed by a pair of alleles which are sex-linked. What is the probability that the male offspring will show the dominant trait?

Explanation

In this problem, we are dealing with a sex-linked trait where the male parent (XbY) carries the recessive allele (b), and the female parent (XBXB) has two dominant alleles (B). The key is to recognize that in birds, males are homogametic, meaning they have two identical sex chromosomes (XY), while females have two different sex chromosomes (XX).The cross between the male (XbY) and the female (XBXB) yields the following gametes:Xb from the male and XB from the female leads to XbXB (female with dominant trait)Xb from the male and XB from the female leads to XbXB (female with dominant trait)Y from the male and XB from the female leads to XBY (male with dominant trait)Y from the male and XB from the female leads to XBY (male with dominant trait)Thus, all male offspring (XBY) will inherit the dominant allele from the mother, resulting in a probability of 1.00 that they will express the dominant trait.The other options are incorrect because they misinterpret the inheritance pattern and the genotypes of the parents involved in the cross.