Asked in UHS MDCAT 2009 2009Moderate

The dimensions of gravitational constant "G" are:

Correct answer: D. [M-1L3T-2]

  • A. [ML-2T-1]
  • B. [ML-2T-2]
  • C. [M2L-2T-1]
  • D. [M-1L3T-2]

Explanation

Explanation: F = G (m1) (m2) / r² G = F (r²) / (m1) (m2) G = [MLT-2] [L²] / [M] [M] = [M-1L³T-2] These dimensions correspond to surface gravity or acceleration due to gravity. These dimensions correspond to force per unit mass or pressure. These dimensions correspond to the inverse of the square of a length or area.

Last updated

About Law of Universal Gravitation

Every two masses attract each other with a force proportional to the product of their masses and inversely proportional to the square of their separation, expressed as F = Gm₁m₂/r². Questions also involve the gravitational constant, vector direction, superposition of gravitational forces, and the distinction between gravitational force and gravitational field strength.

Practise Gravitation

265 free Gravitation MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Exams that ask Physics questions like this

Physics is on 9 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

Related questions