Asked in UHS MDCAT 2015 2015Moderate

The dimensions of pressure is:

Correct answer: D. D

  • A. A
  • B. B
  • C. C
  • D. D

Explanation

The following is the solution:π‘ƒπ‘Ÿπ‘’π‘ π‘ π‘’π‘Ÿπ‘’ = πΉπ‘œπ‘Ÿπ‘π‘’/π΄π‘Ÿπ‘’π‘ŽBy dimensional analysis: π‘ƒπ‘Ÿπ‘’π‘ π‘ π‘’π‘Ÿπ‘’ = π‘˜π‘”. π‘š. π‘ βˆ’2/π‘š2 Therefore, by simplification we get out answer:[MLTβˆ’2]/[L2]=ML-1T-2The correct dimension of pressure: [MLTβˆ’2]/[L2]=ML-1T-2

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About Dimensional Analysis

Dimensional analysis expresses physical quantities through fundamental dimensions such as mass, length and time. It checks dimensional consistency, helps derive relations and converts between unit systems, but cannot determine numerical constants or distinguish quantities with identical dimensions. Dimensional formulae must not be confused with complete physical units.

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