Asked in ETEA MDCAT 2010 2010Moderate

The dimensions of the gravitational constant are:

Correct answer: B. [M-1L3T-2]

  • A. [M2L2T]
  • B. [M-1L3T-2]
  • C. [M2L-2T-2]
  • D. [ML-2T-1]

Explanation

The dimensions of the gravitational constant can be expressed using the equation for Newton's law of universal gravitation:F = Gm1m2 / r²By rearranging the equation, we can determine the dimensions of G:G = Fr² / m1m2The dimensions of the gravitational constant can be derived as follows:[Force] = [Mass][Acceleration]= [Mass][Length] / [Time]3Substituting the dimensions into the equation:G = ([M][L] / [T]²) × [L]² / [M][M]G = M-1L3T-2

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About Law of Universal Gravitation

Every two masses attract each other with a force proportional to the product of their masses and inversely proportional to the square of their separation, expressed as F = Gm₁m₂/r². Questions also involve the gravitational constant, vector direction, superposition of gravitational forces, and the distinction between gravitational force and gravitational field strength.

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