The price of a cellphone was discounted by 25% and then discounted an additional 20%, to become $348. What was the original price of the cellphone before it was discounted twice?
Correct answer: A. $580.00
- A. $580.00
- B. $620.00
- C. $650.00
- D. $680.00
Explanation
To solve this problem, we need to determine the original price of the cellphone before any discounts were applied. Let's use the variable x to represent the original price.The first discount reduces the price by 25%, meaning the new price is 75% of the original price. This can be expressed as 0.75x.The second discount reduces the price by an additional 20%. Now, the price becomes 80% of the already discounted price, which can be expressed as 0.8 * 0.75x = 0.6x.We know the final price after both discounts is $348, so we set up the equation: 0.6x = 348To find the original price, we solve for x:x = 348 / 0.6 = $580Thus, the original price of the cellphone was $580. Option A is correct because it matches this solution. The other options are incorrect because they do not lead to $348 after applying the sequential discounts.
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Quantitative reasoning applies arithmetic and basic algebra to numerical relationships, including percentages, ratios, averages, fractions, proportions, profit and loss, rates, time, work and measurement. Questions focus on translating words into equations, choosing an efficient method and checking whether the result is numerically reasonable.
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