The radius of the moon is 27% off the earth's radius and its mass is 1.2% of the earth's mass. Find the acceleration due to gravity on the surface of the moon:
Correct answer: B. 1.615 m/s2
- A. 0.431 m/s2
- B. 1.615 m/s2
- C. 2.431 m/s2
- D. 3.615 m/s2
- E. 4.431 m/s2
Explanation
Let M & M' be the mass of earth & moon. Also R & R' be their radius respectively. Given is - M' = 1.2% M = 0.012 M R' = 27% R = 0.27 R Gravitationalacceleration on earth's surface is - g = GM / R2 Gravitationalacceleration on supposed planet is - g' = GM' / R'2 g' = G(0.012M) /(0.27R)2 g' = (0.012/0.272)GM/R^2 g' = 0.1646 g g' = 0.1646 × 9.8 g' = 1.613 m/s2 Therefore, acceleration due to gravity on the moon's surface is 1.613 m/s2.
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