Moderate

The rubber cord of a catapult has a cross-sectional area of 1 mm² and a total unstretched length of 10 cm. It is stretched to 12 cm and then released to project a stone of mass 5 g. Taking Young's modulus Y of rubber as 5 × 10⁸ N/m², the velocity of projection will be:

Correct answer: B. 20 m/s

  • A. 20 cm/s
  • B. 20 m/s
  • C. 2 m/s
  • D. None of these

Explanation

The potential energy stored in the stretched cord is E = (1/2)× Stress × Strain × Volume. This stored energy is convertedinto the stone's kinetic energy (1/2)mv². Solving this energybalance equation for velocity gives 20 m/s.

Last updated

About Physics of Solids

Solids are compared through crystal structure, amorphous arrangement, elasticity, plastic deformation, stress, strain and Young’s modulus. Electrical behavior depends on available charge carriers and band structure, so conductors, insulators and semiconductors must be distinguished from mechanical properties such as strength, stiffness and brittleness.

Practise Physics of Solids

320 free Physics of Solids MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Exams that ask Physics questions like this

Physics is on 9 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

Related questions