The velocity with which a projectile must be fired so that it escapes Earth's gravitation does not depend on:
Correct answer: B. Mass of the projectile
- A. Mass of the earth
- B. Mass of the projectile
- C. Radius of the projectile's orbit
- D. Gravitational constant
Explanation
This is the following solution: The correct option is the mass of the projectile: The escape velocity is solely determined by the mass of the celestial body from which the projectile is being launched (in this case, the Earth) and the radius from the center of the body to the projectile's starting point.The escape velocity, denoted as ve, can be calculated using the formula:ve = √((2GM)/r),where G is the gravitational constant, M is the mass of the celestial body (Earth), and r is the distance from the center of the celestial body to the projectile's starting point.
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Newton’s law of universal gravitation relates the force between masses to their masses and separation, while gravitational field strength explains weight and orbital motion. The topic covers satellite velocity and period, escape ideas, weightlessness in free fall, and artificial gravity, which differs from ordinary gravitational attraction.
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