Asked in ETEA MDCAT 2011 2011Moderate

The weight of a pilot when diving down in a jet plane with an acceleration of 9.8m/s2 will become

Correct answer: D. Zero

  • A. Double
  • B. Half
  • C. Negative
  • D. Zero

Explanation

Weight of pilot = Original Weight + Apparent Weight = mg+(-ma) a= 9.8ms-2 So weight of pilot = 0

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