When the lift moves downward with an acceleration "a", the apparent value of "g" inside the lift changes to:
Correct answer: B. g - a
- A. g + a
- B. g - a
- C. g - 2a
- D. g + 2a
Explanation
The apparent weight is the force experienced by an object inside the lift, and it's the force with which the object presses against the floor of the lift. When the lift is moving downward with acceleration a, the effective acceleration acting on the object is g−a because the acceleration due to gravity (g) is partially opposed by the acceleration of the lift (a).
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