wire, suspended vertically from one end, is stretched by attaching a weight of 20 N to the lower end. The weight stretches the wire by 1 mm. How much energy is gained by the wire
Correct answer: A. 0.01J
- A. 0.01J
- B. 0.02J
- C. 0.04J
- D. 1J
Explanation
The energy gained by the wire is given by the formula 1/2 * force * extension. In this case, the force is 20 N and the extension is 0.001 m (1 mm = 0.001 m). Therefore, the energy gained by the wire is 1/2 * (20 N * 0.001 m) = 0.01 J.
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