The given diagram shows a helical spring attached to a fixed surface. The value of spring constant is taken as 'k' 300 N/m and a 100 N weight is attached at the bottom.The extension in the spring will be
Correct answer: A. 0.333 m
- A. 0.333 m
- B. 0.666 m
- C. 3 m
- D. 6 m
Explanation
The correct answer is 0.333 m. When a weight is attached to the spring, it exerts a force on the spring, causing it to extend. By applying Hooke's Law (F = kx), where F is the force, k is the spring constant, and x is the extension, we can calculate the extension in the spring to be 0.333 meters. Options B, C, and D are incorrect because they do not account for the force exerted by the weight of the object, leading to incorrect extension calculations.
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Deformation and elasticity describe how solids change shape or volume under an applied force and return to their original form when the force is removed. Work includes stress, strain, Hooke’s law, elastic limit, Young’s modulus and elastic potential energy, while elastic deformation must be distinguished from permanent plastic deformation.
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