Asked in ETEA MDCAT 2012 2012Moderate

The spring constant of a spring is k. If the spring is cut into two halves then the spring constant of one of the halves is:

Correct answer: C. 2k

  • A. k + 2
  • B. k/2
  • C. 2k
  • D. k

Explanation

According to Hooke's Law, the force exerted by a spring is given by F = -kx, where k is the spring constant and x is the displacement. The spring constant is a measure of the spring's stiffness. When a spring is cut into two equal halves, each half becomes stiffer because the same force is now applied over a shorter distance. Therefore, the spring constant of each half becomes twice the original, or 2k. The other options are incorrect because they do not accurately reflect this relationship. Option A incorrectly adds a constant, Option B incorrectly assumes the spring constant is halved, and Option D assumes the spring constant remains unchanged.

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